A-level course · Lesson 3 of 12

The energy of impacts and airbursts

Impact energies range from a firecracker to the end of the dinosaurs. This lesson quantifies them, compares airbursts with cratering impacts, and introduces how crater size scales with energy.

In this lesson you will
  • Calculate the kinetic energy of an impactor from its size, density and speed.
  • Convert energies to TNT equivalents and compare real events.
  • Explain qualitatively why crater diameter grows much more slowly than energy.

Links to: A-level physics, mechanics: kinetic energy and work; maths: volume of a sphere, standard form and orders of magnitude.

From size to energy

For a roughly spherical impactor of diameter d and density ρ, the mass is m = ρ × (π/6)d³ and the kinetic energy is E = ½mv². Because mass depends on d³ and energy on v², a body twice as large carries eight times the energy at the same speed.

Impact energies are quoted in TNT equivalents: 1 kilotonne (kt) = 4.184 × 10¹² J and 1 megatonne (Mt) = 4.184 × 10¹⁵ J.

Airburst or crater?

Whether energy is released in the air or at the ground depends on size, strength and speed. Stony bodies up to a few tens of metres usually fragment and explode in the atmosphere: Chelyabinsk (2013) released about 0.5 Mt at around 30 km altitude, and Tunguska (1908) about 10 to 15 Mt, flattening some 2,000 km² of forest. Iron bodies are much stronger and can reach the ground at high speed even when tens of metres across, as at Meteor Crater. Bodies larger than a few hundred metres pass through the atmosphere with little loss of speed and always crater.

Crater scaling

Crater diameter does not grow in proportion to energy. Experiments and models show that for large craters, diameter scales roughly as energy to a power of about one quarter to one third, depending on how gravity and target strength limit excavation. A thousand-fold increase in energy therefore produces only a five- to ten-fold increase in diameter. Above a few kilometres on Earth, craters collapse under gravity into complex forms with central peaks or peak rings.

Worked example

The energy of Chelyabinsk

The Chelyabinsk impactor is estimated at 1.2 × 10⁷ kg travelling at 1.9 × 10⁴ m s⁻¹. Calculate its kinetic energy in joules and in kilotonnes of TNT.

  1. E = ½mv² = 0.5 × 1.2 × 10⁷ × (1.9 × 10⁴)².
  2. (1.9 × 10⁴)² = 3.61 × 10⁸ m² s⁻².
  3. E = 0.5 × 1.2 × 10⁷ × 3.61 × 10⁸ = 2.17 × 10¹⁵ J.
  4. In kilotonnes: 2.17 × 10¹⁵ ÷ 4.184 × 10¹² ≈ 520 kt.

Answer: About 2.2 × 10¹⁵ J, or roughly 500 kt of TNT, matching estimates from infrasound and satellite observations.

Activity

Use the impact calculator on this site to find the energy of a 50 m stony body (density 3,000 kg m⁻³) at 17 km s⁻¹, then check it by hand. Repeat for an iron body (7,800 kg m⁻³). Explain why the outcomes predicted by the calculator differ so much for the two compositions.

Quiz

5 questions. Choose an answer to see whether you are right and why. Finish the quiz to complete the lesson.

  1. Question 1By what factor does impact energy increase if an impactor's diameter doubles at the same speed and density?

  2. Question 2How many joules are in 1 megatonne of TNT?

  3. Question 3Why can iron impactors make craters at sizes where stony ones explode in the air?

  4. Question 4If impact energy increases by a factor of 1,000, roughly how much does crater diameter increase?

  5. Question 5A 10 m stony body (ρ = 3,000 kg m⁻³) moves at 20 km s⁻¹. What is its kinetic energy? (V = πd³/6)

Explore on Howardites